If the letters of the word FLOWER are arranged at random, the probability that the order of the consonants is not changed

\frac{50}{720}

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\frac{40}{270}

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\frac{30}{720}

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\frac{20}{720}

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Solution

The correct option is D $\frac{20}{720}$
Order of consonants not to be changed
$F L O W E R$ === Vowels O and E
FLWR__
So O and E have to be arranged in the above spaces
Total no. of ways = $^{5} C_{2} \times 2! = 20$ .
Total no. of arrangements of $F L O W E R$ = $6! = 720$
So $P = 20 / 720$

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If the letters of the word FLOWER are arranged at random, the probability that the order of the consonants is not changed

The correct option is D 20720Order of consonants not to be changedFLOWER === Vowels O and E__F__L__W__R__So O and E have to be arranged in the above spaces Total no. of ways = 5C2×2!=20.Total no. of arrangements of FLOWER =6!=720So P=20/720

The correct option is D $\frac{20}{720}$
Order of consonants not to be changed
$F L O W E R$ === Vowels O and E
FLWR__
So O and E have to be arranged in the above spaces
Total no. of ways = $^{5} C_{2} \times 2! = 20$ .
Total no. of arrangements of $F L O W E R$ = $6! = 720$
So $P = 20 / 720$