If the limiting points of the system of circles x2+y2+2gx+λ(x2+y2+2fy+k)=0 where λ. is a parameter. subtend a right angle at the origin, then k/f2=
A
-1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 2 Limitings points are A(−g1+λ1,−λ1f1+λ1) and B(−g1+λ2,−λ2f1+λ2) where λ1,λ2 are the roots of λ2(f2−k)−kλ+g2=0 OA is perpendicular to OB ⇒λ1fg×λ2fg=−1⇒λ1λ2=−g2f2 ⇒g2f2−k=−g2f2⇒kf2=2