If the line 2x+3y=5 and y=mx+c be parallel, then
If the equation of the normal is y = mx + c to the parabola y2=4ax, then find the value of 'c' in terms of a and m.
If the three lines y=m1x+c1,y=m2x+c2 and y=m3x+c3 are concurrent then show that,
m1(c2−c3)+m2(c3−c1)+m3(c1−c2)=0
If three lines whose equations are y=m1x+c1, y=m2x+c2 and y=m3x+c3 are concurrent, then show that m1(c−2−c3)+m2(c3−c1+m3(c1−c2)=0.