1
Question
If the line 3x + 4y - 1 = 0 touches the circle (x−1)2+(y−2)2=r2, then the value of r will be
If the line 3x + 4y - 1 = 0 touches the circle (x−1)2+(y−2)2=r2, then the value of r will be
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Solution
The correct option is A 2
If the line 3x + 4y - 1 = 0 touches the circle (x−1)2+(y−2)2=r2, then the perpendicular from centre of circle on line is equal to the radius of circle i.e., ∣∣3+8−15∣∣ = r or r = 2.
2
If the line 3x + 4y - 1 = 0 touches the circle (x−1)2+(y−2)2=r2, then the perpendicular from centre of circle on line is equal to the radius of circle i.e., ∣∣3+8−15∣∣ = r or r = 2.