If the line 3x+4y=5 divides the line segment joining the points (1,2) and (−2,3) in the rario λ:1, then the value of |λ| is
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Solution
Given ratio is λ:1 Points are (1,2) and (−2,3) Now, the required point =(1−2λλ+1,3λ+2λ+1) Since this point lies on the line 3x+4y=5 3(1−2λλ+1)+4(3λ+2λ+1)=5⇒3−6λ+12λ+8=5λ+5⇒λ=−6∴|λ|=6