If the line 3x+4y=5 divides the line segment joining the points (1,2) and (−2,3) in the rario λ:1, then the value of |λ| is
Open in App
Solution
Given ratio is λ:1
Points are (1,2) and (−2,3)
Now, the required point =(1−2λλ+1,3λ+2λ+1)
Since this point lies on the line 3x+4y=5 3(1−2λλ+1)+4(3λ+2λ+1)=5⇒3−6λ+12λ+8=5λ+5⇒λ=−6∴|λ|=6