If the line $a x + b y + c = 0$ is a normal to the curve $x y = 1,$ then

a > 0, b < 0

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a < 0, b > 0

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a > 0, b > 0

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a < 0, b < 0

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Solution

The correct options are
A $a > 0, b < 0$
B $a < 0, b > 0$

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Similar questions

a x + b y + c = 0, a b \neq 0

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a x + b y + c = 0

x y + 5 = 0,

a

b

a x + b y + c = 0

x y + 5 = 0

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