If the line a x-b y-c-0 is a normal to the curve x y-1- thenA- a-0- b-0B- a-0- b-0C- a0D- a-b-1

The correct option is C a lt; 0,b gt; 0 Slope of the line a/b is equal to slope of the normal to the curve. ∴ either a gt; 0 amp; b lt; 0 (or) ...

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Standard XII

Mathematics

Second Derivative Test for Local Maximum

If the line a...

Question

If the line ax + by + c=0 is a normal to the curve xy=1, then

a > 0, b > 0

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a < 0,b < 0

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a < 0,b > 0

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a=b=1

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Solution

The correct option is C
a < 0,b > 0

Slope of the line $\frac{- a}{b}$ is equal to slope of the normal to the curve.

$∴$ either a > 0 & b < 0 (or) a < 0 & b > 0.

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If the line ax + by + c=0 is a normal to the curve xy=1, then

The correct option is C a < 0,b > 0 Slope of the line −ab is equal to slope of the normal to the curve. ∴ either a > 0 & b < 0 (or) a < 0 & b > 0.

The correct option is C
a < 0,b > 0

Slope of the line $\frac{- a}{b}$ is equal to slope of the normal to the curve.

$∴$ either a > 0 & b < 0 (or) a < 0 & b > 0.