If the line x-a-y-b-1 touches the circle 2x2-y2-a2 thenA- a-bB- a2-b2C- 2 a2-b2D- a2-2 b2

The correct option is B a2=b2 r=d⇒ a^2 = b^2 ...

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Definition of Circle

If the line x...

Question

If the line $\frac{x}{a} + \frac{y}{b} = 1$ touches the circle $2 (x^{2} + y^{2}) = a^{2}$ then

a=b

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a²=b²

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2a²=b²

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a²=2b²

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Solution

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The equation of the circle with center (– a, – b) and radius √a² – b² is:

The length of common chord of the circles $(x - a)^{2} + y^{2}$ = $a^{2}$ and $x^{2} + (y - b)^{2}$ = $b^{2}$ is

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}}

\frac{a^{2}}{l^{2}} + \frac{b^{2}}{m^{2}}

The length of the chord intercepted by the circle $x^{2} + y^{2} = r^{2}$ on the line $\frac{x}{a} + \frac{y}{b} = 1$

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