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Question

If the line xx1a1=yy1b1=zz1c1 makes an angle θ with the plane a2x+b2y+c2z=d, then = a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)

A
sin θ
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B
cos θ
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C
tan θ
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D
sec θ
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Solution

The correct option is A sin θ
If the angle between plane and line is θ, then the angle between normal to the plane and line is 90θ.

cos(90θ)=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)
Or sin(θ)=a1a2+b1b2+c1c2(a21+b21+c21)(a22+b22+c22)

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