If the line lx+my+n=0 is tangent to the parabola y2=4ax, then
A
mn=al2
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B
lm=an2
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C
ln=am2
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D
None of the above
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Solution
The correct option is Cln=am2 Given parabola, y2=4ax ⇒2ydydx=4a ⇒dydx=2ay ..... (i) Which is the slope of tangent. Given, lx+my+n=0 is an equation of tangent of the parabola y2=4ax. ∴ Slope of tangent =−lm ...... (ii) From Eqs. (i) and (ii) 2ay=−lm⇒y=−2aml ∵y2=4ax ⇒4a2m2l2=4ax ⇒x=am2l2 On putting the values of x and y in the following equation lx+my+n=0 l(am2l2)+m(−2aml)+n=0 am2l−2am2l+n=0 ⇒am2l=n⇒am2=nl which is the required relation.