Question

If the line passing through the points $(-8,3)(2,1)$ is parallel to the line passing through the points $(11,-1)(k,0)$ then the value of $k$ is

• A. $5$
• B. $7$
• C. $\frac{5}{2}$
• D. $6$

Answer 1

Answer: (D)

$6$

slope of the line passing through $(-8,3),(2,1)$ is

$m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{1-3}{2+3}=\frac{-2}{10}=\frac{-1}{5}$

slope of line passing through points $\left(11,-1\right)\&\left(k,u\right)$

$m_2=\frac{y_2-y_1}{x_2-x_2}=\frac{0+1}{k-11}=\frac{1}{k-11}$

since these lines are paralle so,

$m_1=m_2$

$\Rightarrow \frac{-1}{5}=\frac{1}{k-11}$

$\Rightarrow k-11=-5$

$\Rightarrow k=11-5$

$\Rightarrow k=6$