If the line px+qy=r intersects the ellipse x^2+4y^2=4 in points, whose ecentric angles differ by 60 degree, then r^2 is equal to (1) 3/4(4p^2+q^2) (2) 4/3(4p^2+q^2) (3) 2/3(4p^2+q^2) (4) 3/4(p^2+4q^2)

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