The correct option is C the ratio is 2:5 externally
Let A≡(2,−3) and B≡(5,6).
Let y−axis divides the line segment AB internally in the ratio m:n at point H.
Then, H≡(5m+2nm+n,6m−3nm+n)
Since H lies on y−axis, therefore, x−coordinate of H will be zero.
∴5m+2nm+n=0
∴5m=−2n
⇒mn=−25
Hence, y−axis divides the line segment AB externally.
∴H≡(0,2×6−5(−3)2−5)=(0,−9)