If the line x = 1 is the directrix of the parabola y2 – kx + 8 = 0 then positive value of k is _______
4
(1/4)
8
(1/8)
Equation of parabola isy2=k(x−8k)⇒(y−0)2=k(x−8k)∴Equation of directrix is x−8k=−k4⇒x=8k−k4But given x = 1 is directrix ⇒1=8k−k4⇒k=−8,4
The line x-1=0 is the directrix of the parabola y2−kx+8=0. Then one of the values of k is