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Obtaining Centre and Radius of a Circle from General Equation of a Circle

If the line x...

Question

If the line x + 2by + 7 = 0 is diameter of the circle $x^{2} + y^{2} - 6 x + 2 y = 0$ , then b =

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-5

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-1

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Solution

The correct option is D 5
Here the centre of circle (3, -1) must lie on the line x + 2by + 7 = 0
Therefore, 3 - 2b + 7 = 0 $\Rightarrow$ b = 5

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Similar questions

If the line x+2by+7=0 is a diameter of the circle $x^{2} + y^{2} - 6 x + 2 y = 0$ , then b=

2 b y + 7 = 0

^{2}

^{2}

6 y

2 y = 0

x + 2 k y + 3 = 0

x^{2} + y^{2} - 6 x + 2 y = 0

k

\sqrt{10}

2 x + y = 5

x^{2} + y^{2} - 6 x + 2 y = 0

2 x + y = 5

x^{2} + y^{2} - 6 x + 2 y = 0.

\sqrt{10}

2 x + y = 5

x^{2} + y^{2} - 6 x + 2 y = 0

x^{2} + y^{2} - 6 x + 2 y = 0.

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