If the line xcosα+ysinα=p intersects the circle x2+y2=4 at A and B and chord AB makes an angle of 30∘ at a point on the circumference of circle then 3p2=
A
9.00
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B
9
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C
9.0
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Solution
∠AOB=2∠AXB=60∘ ∵p is perpendicualar distance of the given line from origin ∴p=OD
Now In △OAB cos30°=p2 ⇒p=√3 ⇒3p2=9