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Question

If the line x-y+k=0 is a normal to y2=4ax then the value of k is


A

4a

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B

-a

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C

-5a

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D

-3a

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Solution

The correct option is D

-3a


x-y+k=0 y2=4ax
y=x+k
y=mx+c
c=2amam3
=2a.1a.13
C=-3a


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