If the line y = mx + 8 contains the point (-4, 4), calculate the value of m.

-1

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Solution

The correct option is B
1

Puting (-4, 4) in the equation of line y = mx + 8
4 = -4m + 8
4 - 8 = -4m
-4 = -4m
1 = m

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Similar questions

(i) The point (-3, 2) lies on the line ax + 3y + y = 0, calculate the value of a.

(ii) The line y = mx + 8 contains the point (-4, 4), calculate the value of m.

y^{2} = 4 x

y = m x

2

m

(x + 1)^{2} + (y + 1)^{2} = r^{2}

\sqrt{3 - 2 \sqrt{2}}

\sqrt{2} - 1

\sqrt{2} + 1

\sqrt{3} - \sqrt{2}

\sqrt{3} + \sqrt{2}

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