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Question

If the line y=mx+a meets the parabola y2=4ax in two points whose abcissa are x1 and x2 , then x1+x2=0 if

A
m=1
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B
m=1
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C
m=2
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D
m=12
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Solution

The correct option is C m=2
y2=4ax

y=mx+a On substituting y from this line to the parabola equation

(mx+a)2=4ax
m2x2+(2am4a)x+a2=0

Sum of roots=x1+x2=(2am4a)m2=0

So, m=2

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