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Question

If the line y3x+3=0 cuts the parabola y2=x+2 at A and B, then PA. PB is equal to (where P(3,0)

A
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B
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C
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D
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Solution

The correct option is A
y3x+3=0 can be rewritten as
y032 =x312=r (1)
Solving (1) with the parabola y2=x+2 3r24r232=0 PAPB=r1r2=4(3+2)3

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