If the lines 2x+3y−13=0, x−4y+10=0, ax+5y−21=0 are concurrent then the value of a is:
A
1
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B
2
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C
3
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D
−2
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Solution
The correct option is A3 As they are concurrent so determiant of coefficient matrix will be zero ∣∣
∣∣23−131−410a5−21∣∣
∣∣=2[84−50]−3[−21−10a]−13[5+4a] ⇒68+63+30a−65−52a=0 ⇒66−22a=0 ⇒a=3.