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Question

If the lines 2y−a2x=3 and 2y−(4ax+1)=0 are parallel, find the value of a.


A

2

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B

4

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C

6

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D

8

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Solution

The correct option is B

4


The slope of the given lines 2ya2x=3 and 2y(4ax+1)=0 are -
y=a2x2+32 and y=4ax2+12
Here, m1=a22
and m2=2a
Since lines are parallel
m1=m2
a22=2aa=4


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