If the lines 2y−a2x=3 and 2y−(4ax+1)=0 are parallel, find the value of a.
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The slope of the given lines 2y−a2x=3 and 2y−(4ax+1)=0 are - y=a2x2+32 and y=4ax2+12 Here, m1=a22 and m2=2a Since lines are parallel m1=m2 ⇒ a22=2a⇒a=4
If 2y –a2x = 3 and 2y – (4ax +1) = 0 are parallel, find the value of a, where a is a natural number.
The value of a for which the lines x=1, y=2 and a2x+2y−20=0 are concurrent is:
If the point P(3,a) lies on the line x + 2y = 3, then find the value of a.