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Question

If the lines x+12=y−11=z+13 and −x+22=y−k3=z4 are coplanar, then the value of k is

A
112
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B
112
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C
92
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D
92
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Solution

The correct option is A 112
To find: value of k
x+12=y11=z13=m
x=2m1; y=m+1; z=3m1
x+22=yk3=z4=n
x=2n2;z=4n;y=3n+k
2m1=2n2
m=2n12
Also, 3m1=4n
3(2n1)21=4n
6n5=8n
n=52
m+1=3n+k
2n12+1=3n+k
2n+123n=k
k=14n2
=1+102
k=112.

1180430_1260439_ans_f4e02d3270014a74bbcbc6d38774db7f.jpg

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