Area of Triangle with Coordinates of Vertices Given
If the lines ...
Question
If the lines
x−21=y−31=z−4λ and
x−1λ=y−42=z−51
intersect, then-
A
λ=−1
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B
λ=2
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C
λ=−3
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D
λ=0
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Solution
The correct options are Aλ=−1 Dλ=0 We know for two lines to intersect, ∣∣
∣∣x2−x1y2−y1z2−z1a1b1c1a2b2c2∣∣
∣∣=0 ⇒∣∣
∣∣−11111λλ21∣∣
∣∣=0⇒−1(1−2λ)−1(1−λ2)+1(2−λ)=0 ⇒λ2+λ=0⇒λ=0,−1