Question 7
If the lines given by 3x + 2ky = 2 and 3x + 5y = 1 are parallel, then the value of k is
(a) −54
(b) 12
(c) 154
(d) 32
Answer - C
Condition for parallel lines is
a1a2=b1b2≠c1c2
Given 3x + 2ky – 2 = 0
And 2x + 5y – 1 = 0
Here, a1=3, b1=2k, c1=−2
and a2=2, b2=5, c2=−1
From Eq (i), 32=2k5
∴k=154
Also, c1c2=−2−1=2
Thus, a1a2=b1b2≠c1c2