If the lines p1x+q1y=1,p2x+q2y=1 and p3x+q3y=1 be concurrent, then the points (p1,q1),(p2,q2) and (p3,q3) ,
A
are collinear
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B
form an equilateral triangle
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C
form a scalene triangle
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D
form a right angled triangle
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Solution
The correct option is A are collinear p1x+q1y=1,p2x+q2y=1p3x+q3y=1 Given lines are concurrent ⇒∣∣
∣∣p1q11p2q21p3q31∣∣
∣∣=0 ⇒p1(q2−q3)−q1(p2−p3)+(p2q3−p3q2)=0 ⇒(p1q2−p2q1)+(p2q3−p3q2)+(p3q1−p1q3)=0 The left hand side of the above equation is also equal to twice the area of a triangle with coordinates (p1,q1),(p2,q2),(p3,q3) Since it is equal to zero, (p1,q1),(p2,q2),(p3,q3) are collinear.