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Question

If the lines PQ and RS intersect at a point T such that ∠PRT = 40o, ∠RPT = 95o and ∠TSQ = 75o. Then the measure of ∠SQT is:


A

50o

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B

45o

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C

60o

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D

90o

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Solution

The correct option is C

60o


In ∆ PRT

ÐPRT + ÐRPT + ÐPTR = 180o (angle sum property)

ÐPTR = 45o

ÐPTR = ÐSTQ (vertically opposite angles)

Now, in ∆ STQ

ÐSQT + ÐSTQ + ÐTSQ = 180o (angle sum property)

ÐSQT = 60o


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