If the lines PQ and RS intersect at a point T such that ∠PRT = 40o, ∠RPT = 95o and ∠TSQ = 75o. Then the measure of ∠SQT is:
60o
In ∆ PRT
ÐPRT + ÐRPT + ÐPTR = 180o (angle sum property)
ÐPTR = 45o
ÐPTR = ÐSTQ (vertically opposite angles)
Now, in ∆ STQ
ÐSQT + ÐSTQ + ÐTSQ = 180o (angle sum property)
ÐSQT = 60o