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Question

If the lines x/3+y/4= 7 and 3x+ky=11 are perpendicular to each other find the value of k.

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Solution

The given equation of first line is : x3 + y4 = 74x + 3y = 84y = -43x + 843 .....1Now, slope of the line 1 is, m1 = -43The equation of the other line is :3x + ky = 11y = -3kx + 11 .....2Now, slope of line 2 is, m2 = -3kSince, line 1 is to line 2, then m1 . m2 = -1-43 × -3k = -14k = -1k = -4

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