Given lines : L1:x=y2=z,L2:x−2−2=y−44=z−2−1 L3:4x=y+h1=−9z+k−2
Any points on line L1=(λ,2λ,λ) and any points on L2=(2−2μ,4+4μ,2−μ)
At point of intersection :
λ=2−2μ⋯(i)2λ=4+4μ⋯(ii)λ=2−μ⋯(iii)
Solving (i),(ii):μ=0,λ=2
So points of intesection is: (2,4,2) lie on line L3 for concurrecny
⇒8=4+h1=−18+k−2⇒h=4,k=2