If the lines x+y=a and x−y=b touch the curve y=x2−3x+2 at the points where the curve intersects the x-axis, then ab is equal to
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Solution
y=x2−3x+2 ⇒y=(x−1)(x−2)
Touches x-axis at (1,0) and (2,0)
Slope of lines x+y=a and x−y=b are −1 and 1.
So, the equation 1 is y−0=−1(x−1) ⇒x+y=1⇒a=1⋯(i)
So, the equation 2 is y−0=x−2 ⇒x−y=2⇒b=2⋯(ii)
Equation (i)/(ii) ab=12