If the lines y = 3 + 7 & 2y + p = 3 are || to each other, find the value of p.
p = 6
p = -6
p = -8
p = 8
p = 7
Find the value of ‘p’ for which the lines 2 + 3y – 7 = 0 & 4y + – 12 = 0 are ⊥ to each other.
If the lines y = 3x + 7 and 2y + px = 3 are perpendicular to each other, find the value of p.
If p = −2, find the value of:
(i) 4p + 7
(ii) −3p2 + 4p + 7
(iii) −2p3 − 3p2 + 4p + 7
If 'p' and 'q' are rational numbers, then find 'p' and 'q' given that 3+√73−√7=p+q√7