wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the lines (y−b)=m1(x+a) and (y−b)=m2(x+a) are two tangents to the parabola y2=4ax then

A
m1+m2=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
m1m2=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
m1m2=1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
m1+m2=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A m1m2=1
Condition for tangency is c=am
Hence
(am1b)m1=a
(am2b)m2=a
On comparing we get
am12bm1=am22bm2
a(m21m22)=b(m1m2)

a(m1m2)(m1+m2)=b(m1m2)

m1+m2=ba
Now (m1ba)m1=1
m1m2=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon