If the locus of centre of circle which cuts the circles x2+y2+4x−6y+9=0 and x2+y2−4x+6y+4=0 orthogonally is ax+by+c=0 then a+b+c is equal to
Open in App
Solution
∵ Centre of circle which cuts the given two circles orthogonally lies on radical axis, ∴ Locus of centre (h,k) will lies on S1−S2=0 ⇒8h−12k+5=0 So, locus is 8x−12y+5=0 ∴a+b+c=8−12+5=1