If the magnet is suspended at an angle 30^o to the magnetic meridian, the dip needle makes an angle 60^o with the horizontal. What is the true dip?

tan^-1 (2/3)

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tan^-1 (1/3)

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tan^-1 (3/2)

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tan^-1 (3)

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Solution

The correct option is C
tan^-1 (3/2)

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Similar questions

If a magnet is suspended at an angle 30 $^{0}$ to the magnetic meridian, the dip needle makes an angle of $60^{o}$ with the horizontal. The true value of dip is :

The real angle of dip, if a magnet is suspended at an angle of $30^{0}$ to the magnetic meridian and the dip needle makes an angle of 45 $^{0}$ with horizontal is :

Q. If a magnet is suspended at an angle

30^{\circ}

to the magnetic meridian, it makes an angle of

45^{\circ}

with the horizontal. The real dip is

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If the magnet is suspended at an angle 30o to the magnetic meridian, the dip needle makes an angle 60o with the horizontal. What is the true dip?

The correct option is C tan-1 (3/2)

If the magnet is suspended at an angle 30^o to the magnetic meridian, the dip needle makes an angle 60^o with the horizontal. What is the true dip?

The correct option is C
tan^-1 (3/2)