Question

If the magnetic field of a plane electromagnetic wave is given by (The speed of light $=3\times {10}^8/m/s)B=100\times {10}^{-6}\sin [2\pi \times 2\times {10}^{15}(t-\frac{x}{c})]$ then the maximum electric field associated with it is

• A. $4\times {10}^{4}N/C$
• B. $4.5\times {10}^{4}N/C$
• C. $6\times {10}^{4}N/C$
• D. $3\times {10}^{4}N/C$

Answer 1

The correct option is D $3\times {10}^{4}N/C$

$E_0=B_0\times c$
$=100\times {10}^{-6}\times 3\times {10}^8$
$=3\times {10}^{4}N/C$
$\therefore$ correct answer is $3\times {10}^{4}N/C$.