If the magnitude of its angular speed at $t = 3.0 s$ is $x r a d / s$ , find $2 x$ .

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Solution

$\int d ω = \int α d t$
$∴ \int_{65}^{ω} d ω = \int_{0}^{3} (- 10 - 5 t) d t$
$∴ ω = 65 - [10 t + 2.5 t^{2}]_{0}^{3}$
$- 12.5 r a d / s$

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If the magnitude of its angular speed at t=3.0s is xrad/s, find 2x.

∫dω=∫αdt∴∫ω65dω=∫30(−10−5t)dt∴ω=65−[10t+2.5t2]30−12.5rad/s

If the magnitude of its angular speed at $t = 3.0 s$ is $x r a d / s$ , find $2 x$ .

$\int d ω = \int α d t$
$∴ \int_{65}^{ω} d ω = \int_{0}^{3} (- 10 - 5 t) d t$
$∴ ω = 65 - [10 t + 2.5 t^{2}]_{0}^{3}$
$- 12.5 r a d / s$