If the magnitudes of vectors a- and b- are 1 and 2 respectively and a-b- - 1- then find the angle between those vectors-

|a⃗ |=1 , |b⃗ |=2 and a⃗·b⃗ =1 #160;We know that a⃗·b⃗ =|a⃗ | |b⃗ | cos θ so we get cos θ = 1 / 2 So θ = 60 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Applications of Dot Product

If the magnit...

Question

If the magnitudes of vectors $\to a$ and $\to b$ are $1$ and $2$ respectively and $\to a \cdot \to b = 1$ , then find the angle between those vectors.

Open in App

Solution

Suggest Corrections

Similar questions

Find the angle between two vectorsandwith magnitudesand 2, respectively having.

\to a

\to b

\to a \cdot \to b < 0

| \to a \cdot \to b | = | \to a \times \to b |

\to a

\to b

The angle between two vectors $\to a a n d \to b$ with magnitudes $\sqrt{3}$ and 4, respectively and $\to a . \to b = 2 \sqrt{3}$ is

(a) $\frac{π}{6}$

(b) $\frac{π}{3}$

(d) $\frac{5 π}{2}$

\to a

\to b

1

120^{\circ}

\to b

\to b - \to a

If \to a

\to b

| \to a \cdot \to b | = | \to a \times \to b |

\to a \cdot \to b < 0,

\to a

\to b

Join BYJU'S Learning Program