If the mass of block is $m = 32.96 k g$ and the volume of block is $16 m^{3}$ , then the density of material will be (upto only two significant digit)

2.06 k g / m^{3}

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2.0 k g / m^{3}

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2.1 k g / m^{3}

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1.9 k g / m^{3}

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Solution

The correct option is C $2.1 k g / m^{3}$
$d = \frac{m a s s}{v o l u m e} = \frac{32.96}{16} = 2.06$
but answer must hold only 2 significant digits,
hence $d = 2.1 k g / m^{3}$

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