If the mass of neutrons is doubled & mass of an electron is halved then find out the new atomic mass of $_{6} C^{12} .$ and the percent by which it is increased?

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Solution

$_{6} C^{12} \to e = 6$

Number of protons = $6 = 6 a m u$
Number of neutrons = $6 = 6 a m u$

Total mass = $(6 + 6) = 12 a m u$

Mass of the electron is negligible.

If the mass of the neutron is doubled, then the total mass = $(6 \times 2) + 6 =$ $18 a m u$

Therefore, the % of the increase = $= \frac{18 - 12}{12} \times 100 = 50 %$

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If the mass of neutrons is doubled & mass of an electron is halved then find out the new atomic mass of 6C12. and the percent by which it is increased?

6C12→e=6Number of protons = 6=6amuNumber of neutrons = 6=6amuTotal mass = (6+6)=12amuMass of the electron is negligible.If the mass of the neutron is doubled, then the total mass = (6×2)+6= 18amuTherefore, the % of the increase = =18−1212×100=50%

If the mass of neutrons is doubled & mass of an electron is halved then find out the new atomic mass of $_{6} C^{12} .$ and the percent by which it is increased?