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Question

If the mass of SO2 used in the reaction 2SO2+O2SO3 is 2g then the mass of SO3 produced is:

A
2.5g
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B
2g
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C
1g
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D
1.5g
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Solution

The correct option is A 2.5g
2SO2+O2SO3
Here the mole ratio between S02 and SO3 is 2:2 = 1.
Here we used 2 g of SO2, so we need to convert that amount into moles.
Sulphur dioxide has molar mass of 64 g/mol. So,
2g64g/mol = 0.03125 mol of SO2
Sulphur trioxide has molar mass of 80 g/mol. So,
0.03125 mol. 80 g/mol = 2.5 g of SO3
Sp, 2.5 grams of sulphur trioxide was produced.

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