If the mass of the electron is reduced to half, then the Rydberg constant:

remains unchanged

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becomes half

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becomes double

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becomes one fourth

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Solution

The correct option is C becomes half
Rydberg constant is given by formula:

$R_{H} = \frac{2 π^{2} Z^{2} m e^{4} k^{2}}{c h^{3}}$

$R_{H}$ is directly proportional to mass of electron $m$ .

So, $R_{H}$ will become half when mass $m$ will be half.

Hence, option B is correct.

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If the mass of the electron is reduced to half, then the Rydberg constant:

The correct option is C becomes halfRydberg constant is given by formula:RH=2π2Z2me4k2ch3RH is directly proportional to mass of electron m. So, RH will become half when mass m will be half. Hence, option B is correct.

The correct option is C becomes half
Rydberg constant is given by formula:

$R_{H} = \frac{2 π^{2} Z^{2} m e^{4} k^{2}}{c h^{3}}$

$R_{H}$ is directly proportional to mass of electron $m$ .

So, $R_{H}$ will become half when mass $m$ will be half.

Hence, option B is correct.