Question

If the mass of the moving object is decreased 1/4th of it's mass and the velocity is increased to twice its previous velocity,what will be the kinetic energy of the object from the following

Answer 1

Kinetic Energy = 1/2 m v^2

Let the initial mass be m and initial velocity be v

Initial Kinetic Energy = 1/2 m v^2

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Final mass = m/4
Final velocity = 2v

Final Kinetic Energy = 1/2 × m/4 × (2v)^2

=> 1/2 × m/4 × 4v^2

=> 1/2 × m × v^2

=> 1/2 m v^2

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Since Final and Initial Kinetic Energy is coming to be equal i.e. 1/2 m v^2 there will be no change in the Kinetic Energy.