Question

If the mass of the particle is $m=1.0\times {10}^{-30}kg$ and $a=6.6nm$, the energy ofthe particle in its ground state is closest to

• A. 0.8 meV
• B. 8 meV
• C. 80 meV
• D. 800 meV

Answer 1

The correct option is B 8 meV

The situation is studied as a particle in a box problem.

According to the model, energy in n'th state is given by $\frac{n^2{h}^2}{8m{a}^2}=\frac{1^2\times (6.626\times {10}^{-34}{)}^2}{8\times {10}^{-30}\times (6.6\times {10}^{-9}{)}^2\times 1.6\times {10}^{-19}}=8meV$