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Standard XII

Chemistry

Concentration Terms

If the mass r...

Question

If the mass ratio of non-reacting gases $O_{2}$ and $N_{2}$ in a vessel is 2 : 7, then the ratio of their molecules will be:

1 : 2

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3 : 5

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2 : 7

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1 : 4

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Solution

The correct option is D 1 : 4
$\frac{M_{O_{2}}}{M_{N_{2}}}$ = $\frac{2}{7}$
$\frac{N_{O_{2}}}{N_{N_{2}}}$ = $\frac{2 / 32}{7 / 28}$ = $\frac{1}{4}$
But number of moles is directly proportional to number of molecules
Therefore, The ratio of number of molecules= $\frac{N_{O_{2}}}{N_{N_{2}}} = 1 : 4$

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If the mass ratio of non-reacting gases O2 and N2 in a vessel is 2 : 7, then the ratio of their molecules will be:

The correct option is D 1 : 4MO2MN2= 27NO2NN2= 2/327/28=14But number of moles is directly proportional to number of moleculesTherefore, The ratio of number of molecules= NO2NN2=1:4

If the mass ratio of non-reacting gases $O_{2}$ and $N_{2}$ in a vessel is 2 : 7, then the ratio of their molecules will be:

The correct option is D 1 : 4
$\frac{M_{O_{2}}}{M_{N_{2}}}$ = $\frac{2}{7}$
$\frac{N_{O_{2}}}{N_{N_{2}}}$ = $\frac{2 / 32}{7 / 28}$ = $\frac{1}{4}$
But number of moles is directly proportional to number of molecules
Therefore, The ratio of number of molecules= $\frac{N_{O_{2}}}{N_{N_{2}}} = 1 : 4$