If the mass shown in figure is slightly displaced and then let go, then the system shall oscillate with a time period of

2 π \sqrt{\frac{m}{3 k}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 π \sqrt{\frac{3 m}{2 k}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 π \sqrt{\frac{2 m}{3 k}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 π \sqrt{\frac{3 k}{m}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 π \sqrt{\frac{3 m}{2 k}}$
Equivalent spring constant of the above system $k_{e q} = (k + k) ∥ k = 2 k ∥ k$
$⟹ k_{e q} = \frac{2 k \times k}{2 k + k} = \frac{2 k}{3}$
Time period of SHM $T = 2 π \sqrt{\frac{m}{k_{e q}}}$
$∴$ $T = 2 π \sqrt{\frac{3 m}{2 k}}$

Suggest Corrections

Similar questions

Q. A body of mass

^{'} m^{'}

hangs from three springs, each of spring constant

^{'} k^{'}

as shown in the figure. If the mass is slightly displaced and let go, the system will oscillate with time period

Q. A body of mass

m

hangs from three springs, each of spring constant

K

, as shown. If the mass is slightly displaced and released, the system will oscillate with time period of

A particle of mass m is attached to three identical springs A, B and C each of force constant k as shown in figure. If the particle of mass m is pushed slightly against the spring A and released, the time period of oscillation is:

Q. Find the period of small oscillations of the bob of mass

m

shown in the figure. Given, mass of the rod is also

m

Q. The ends of a rod of length

l

and mass

m

are attached to two identical springs as shown in figure. The rod is free to rotate about its centre

^{'} O^{'}

. The rod is depressed slightly at end

A

and released. The time period of the resulting oscillation is

Join BYJU'S Learning Program

If the mass shown in figure is slightly displaced and then let go, then the system shall oscillate with a time period of

The correct option is B 2π√3m2kEquivalent spring constant of the above system keq=(k+k)∥k=2k∥k⟹ keq=2k×k2k+k=2k3Time period of SHM T=2π√mkeq∴ T=2π√3m2k

The correct option is B $2 π \sqrt{\frac{3 m}{2 k}}$
Equivalent spring constant of the above system $k_{e q} = (k + k) ∥ k = 2 k ∥ k$
$⟹ k_{e q} = \frac{2 k \times k}{2 k + k} = \frac{2 k}{3}$
Time period of SHM $T = 2 π \sqrt{\frac{m}{k_{e q}}}$
$∴$ $T = 2 π \sqrt{\frac{3 m}{2 k}}$