If the max. and min. values of △= ∣∣
∣
∣∣1+sinxcos2xsin2xsin2x1+cos2xsin2xsinxcos2x1+sinx∣∣
∣
∣∣ are α and β, then
A
α+β99=4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
α3+β17=26
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
α2n−β2n is always an even integer for n∈ N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
a triangle having as α,β, and α−β.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are Aα+β99=4 Bα3+β17=26 Cα2n−β2n is always an even integer for n∈ N Apply R1−R2 and R2−R3 and expanding △=2+sin2x. ∴ Max. value = 2+1=3 =α and min. value = 2-1 =1=β Hence (a), (b), (c) are correct. (d) option is not possible as the sides will be 3, 1 and 2. Sum of two sides 2+1=3 = 3rd side whereas in a triangle sum of two sides is always greater than the third side.