If the maximum height and horizontal range of a projectile are same. Then, projection angle is
A
45∘
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B
30∘
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C
tan−13
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D
tan−14
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Solution
The correct option is Dtan−14 According to question, R=H ⇒2u2sinαcosαg=u2sin2α2g where all the symbols have their usual meaning. ⇒sinα(2cosα−sinα2)=0 ⇒tanα=4 ⇒α=tan−14.