If the maximum velocity and acceleration of the particle executing SHM are equal in magnitude, the time period will be

1.57

sec

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3.14

sec

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6.28

sec

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12.56

sec

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Solution

The correct option is C $6.28$ sec
Hence, option $C$ is correct answer.

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Similar questions

The maximum speed of a particle executing S.H.M. is 1m/s and its maximum acceleration is 1.57m/ $s e c^{2}$ . The time period of the particle will be

[DPMT 2002]

If the maximum velocity and accelaration of a particle executing SHM are equal in magnitude,the time period will be :

A)1.57sec B)3.14sec C)6.28sec D)12.56sec

100 c m s / s e c

157 c m / s e c^{2}

S H M

1 c m, 1 c m / s e c

1 c m / s e c^{2}

π

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