The correct option is C 4
a,2a,....,50a are the observation so, total no. of observation is 50
So, median M=(502)th+(502+1)th2=25a+26a2=512
Mean deviation about median=n∑i=1|xi−M|n,n=50
Put the value of xi and M
So, 50=|a−25.5a|+|2a−25.5a|+...+|50a−25.5a|50⇒50=24.5|a|+23.5|a|+...0.5|a|+0.5|a|+....+24.5|a|50
⇒50=2(0.5|a|+1.5|a|+...+24.5|a|50⇒50=|a|(1+2+...+4950=|a|252(1+49)50|a|=50×5025×25=4